A potter鈥檚 wheel of radius 47.54 cm and mass 108.4 kg is freely rotating at 49.2 rev/min. The potter can stop?

A potter鈥檚 wheel of radius 47.54 cm and mass 108.4 kg is freely rotating at 49.2 rev/min. The potter can stop the wheel in 6.469 s by pressing a wet rag against the rim and exerting a radially inward force of 66.7 N.


What is the angular acceleration of the wheel?





part 2





How much torque does the potter apply to the wheel?|||Hello





the frequency of the wheel is 49,2/60 = 0,82 Hz


蠅 = 2pif = 5,1522 rad/s (= angular frequency)


伪 = 5,1522/6,469 = 0,79644 rad/s^2 (angular acceleration = rather - 0,7944 rad/s^2 when it is called acceleration).





蟿 = I*伪 = (1/2 mR^2)*伪


= (0.5*108,4 kg *0,4754^2 m^2 )*0,79644 rad/s^2 = 9,7559 Nm





Regards